What is the derivative of 2*sin(2x) ?

The derivative of 2*sin(2x) is 4cos(2x)

What is the first derivative of 2*sin(2x) ?

The first derivative of 2*sin(2x) is 4cos(2x)

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\frac{d}{d x} (2 \cdot sin (2 x))

4 cos (2 x)

Solution steps

\frac{d}{d x} (2 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 2 cos (2 x) \cdot 2

Simplify

= 4 cos (2 x)

\frac{d}{d x} (a \cdot cos (x))

\int \frac{u}{2} d u

\int t^{7} e^{t^{4}} d t

\int x^{2} \cdot e^{- 2 x} d x

\int \frac{3 x ^{2} - 5 x}{x} d x

What is the derivative of 2*sin(2x) ?
The derivative of 2*sin(2x) is 4cos(2x)
What is the first derivative of 2*sin(2x) ?
The first derivative of 2*sin(2x) is 4cos(2x)