What is the derivative of 2x^3-2x+1 ?

The derivative of 2x^3-2x+1 is 6x^2-2

What is the first derivative of 2x^3-2x+1 ?

The first derivative of 2x^3-2x+1 is 6x^2-2

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\frac{d}{d x} (2 x^{3} - 2 x + 1)

6 x^{2} - 2

Solution steps

\frac{d}{d x} (2 x^{3} - 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 6 x^{2} - 2 + 0

Simplify

= 6 x^{2} - 2

ln (5 x + ln (3 x))

\frac{\partial}{\partial y} (2 x^{2} + 3 y^{2})

\frac{d}{d x} (1700 e^{x})

\int (6 x^{2} y - 3 x y) d y

\int 3 sin (2 θ) d θ

What is the derivative of 2x^3-2x+1 ?
The derivative of 2x^3-2x+1 is 6x^2-2
What is the first derivative of 2x^3-2x+1 ?
The first derivative of 2x^3-2x+1 is 6x^2-2