What is the solution for y^'=\sqrt[6]{x^5}-x^{sqrt(2)} ?

The solution for y^'=\sqrt[6]{x^5}-x^{sqrt(2)} is y= 6/11 x^{11/6}-(sqrt(2)-1)x^{sqrt(2)+1}+c_{1}

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y^'=\sqrt[6]{x^5}-x^{sqrt(2)}

y = \frac{6}{11} x^{\frac{11}{6}} - (2 - 1) x^{2 + 1} + c_{1}

Solution steps

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \frac{6}{11} x^{\frac{11}{6}} - (2 - 1) x^{2 + 1} + c_{1}

y^{2} = 2 x - 2, y = x - 5

\frac{\partial}{\partial x} (cos (x^{2} y))

\int - 2 x + 18 x^{2} - 4 x^{3} + 18 d x

x \to 0 + lim (e^{- \frac{2}{x}})

\frac{\partial}{\partial x} (\frac{5 x}{y})

What is the solution for y^'=\sqrt[6]{x^5}-x^{sqrt(2)} ?
The solution for y^'=\sqrt[6]{x^5}-x^{sqrt(2)} is y= 6/11 x^{11/6}-(sqrt(2)-1)x^{sqrt(2)+1}+c_{1}