What is the derivative of ln(2x^2+1) ?

The derivative of ln(2x^2+1) is (4x)/(2x^2+1)

What is the first derivative of ln(2x^2+1) ?

The first derivative of ln(2x^2+1) is (4x)/(2x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

ln (2 x^{2} + 1)

\frac{4 x}{2 x ^{2} + 1}

Solution steps

\frac{d}{d x} (ln (2 x^{2} + 1))

Apply the chain rule:

\frac{1}{2 x ^{2} + 1} \frac{d}{d x} (2 x^{2} + 1)

= \frac{1}{2 x ^{2} + 1} \frac{d}{d x} (2 x^{2} + 1)

\frac{d}{d x} (2 x^{2} + 1) = 4 x

= \frac{1}{2 x ^{2} + 1} \cdot 4 x

Simplify

\frac{1}{2 x ^{2} + 1} \cdot 4 x : \frac{4 x}{2 x ^{2} + 1}

= \frac{4 x}{2 x ^{2} + 1}

\frac{d}{d x} (\frac{3}{x - 8})

\int \frac{1}{sin ^{2} ( 5 x )} d x

\frac{d}{d z} (x y z)

\frac{( 2 x + 1 )}{x ^{2}}

\int \frac{x ^{2} - 2}{x ^{2}} d x

What is the derivative of ln(2x^2+1) ?
The derivative of ln(2x^2+1) is (4x)/(2x^2+1)
What is the first derivative of ln(2x^2+1) ?
The first derivative of ln(2x^2+1) is (4x)/(2x^2+1)