What is the solution for (dy)/(dx)+y= 1/(1+x^2) ?

The solution for (dy)/(dx)+y= 1/(1+x^2) is y=(integral of \frac{e^x)/(1+x^2)}{e^x}

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(dy)/(dx)+y= 1/(1+x^2)

\frac{d y}{d x} + y = \frac{1}{1 + x ^{2}}

y = \frac{\int \frac{e ^{x}}{1 + x ^{2}} d x}{e ^{x}}

Solution steps

\frac{d y}{d x} + y = \frac{1}{1 + x ^{2}}

Solve linear ODE:

y = \frac{\int \frac{e ^{x}}{1 + x ^{2}} d x}{e ^{x}}

y = \frac{\int \frac{e ^{x}}{1 + x ^{2}} d x}{e ^{x}}

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What is the solution for (dy)/(dx)+y= 1/(1+x^2) ?
The solution for (dy)/(dx)+y= 1/(1+x^2) is y=(integral of \frac{e^x)/(1+x^2)}{e^x}