What is the derivative of f(x)=ln(1+x) ?

The derivative of f(x)=ln(1+x) is 1/(1+x)

What is the first derivative of f(x)=ln(1+x) ?

The first derivative of f(x)=ln(1+x) is 1/(1+x)

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derivative of

f (x) = ln (1 + x)

\frac{1}{1 + x}

Solution steps

\frac{d}{d x} (ln (1 + x))

Apply the chain rule:

\frac{1}{1 + x} \frac{d}{d x} (1 + x)

= \frac{1}{1 + x} \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= \frac{1}{1 + x} \cdot 1

Simplify

= \frac{1}{1 + x}

\frac{d}{d x} (ln (\frac{2 x}{sin ( x )}))

y = \frac{3}{sin ( 2 x )}

x \to 1 lim (\frac{( x + 3 )}{2})

\int (a x + b)^{n} d x

\int 27 - 6 x - x^{2} d x

What is the derivative of f(x)=ln(1+x) ?
The derivative of f(x)=ln(1+x) is 1/(1+x)
What is the first derivative of f(x)=ln(1+x) ?
The first derivative of f(x)=ln(1+x) is 1/(1+x)