What is the tangent of f(x)=x^{cos(x)},\at x=pi ?

The tangent of f(x)=x^{cos(x)},\at x=pi is y=-1/(pi^2)x+2/pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^{cos(x)},\at x=pi

tangent of

f (x) = x^{c o s (x)}, at x = π

y = - \frac{1}{π ^{2}} x + \frac{2}{π}

Solution steps

Find the tangent point:

(π, \frac{1}{π})

Find the slope of

f (x) = x^{c o s (x)} : \frac{df ( x )}{d x} = x^{c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x})

Compute the slope of

f (x) = x^{c o s (x)}

x = π : m = - \frac{1}{π ^{2}}

Find the line with slope m=

- \frac{1}{π ^{2}}

and passing through

(π, \frac{1}{π}) : y = - \frac{1}{π ^{2}} x + \frac{2}{π}

y = - \frac{1}{π ^{2}} x + \frac{2}{π}

\int - 3 x + 2 x d x

\int (11 - x) d x

x \to 5 + lim (\frac{3}{x - 5})

\int_{0}^{\frac{π}{12}} 6 tan (3 x) d x

What is the tangent of f(x)=x^{cos(x)},\at x=pi ?
The tangent of f(x)=x^{cos(x)},\at x=pi is y=-1/(pi^2)x+2/pi