What is the derivative of f(x)=(10x+x^2)/((5+x)^2) ?

The derivative of f(x)=(10x+x^2)/((5+x)^2) is (50)/((5+x)^3)

What is the first derivative of f(x)=(10x+x^2)/((5+x)^2) ?

The first derivative of f(x)=(10x+x^2)/((5+x)^2) is (50)/((5+x)^3)

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derivative of

f (x) = \frac{10 x + x ^{2}}{( 5 + x ) ^{2}}

\frac{50}{( 5 + x ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{10 x + x ^{2}}{( 5 + x ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 10 x + x ^{2} ) ( 5 + x ) ^{2} - \frac{d}{d x} ( ( 5 + x ) ^{2} ) ( 10 x + x ^{2} )}{( ( 5 + x ) ^{2} ) ^{2}}

\frac{d}{d x} (10 x + x^{2}) = 10 + 2 x

\frac{d}{d x} ((5 + x)^{2}) = 2 (5 + x)

= \frac{( 10 + 2 x ) ( 5 + x ) ^{2} - 2 ( 5 + x ) ( 10 x + x ^{2} )}{( ( 5 + x ) ^{2} ) ^{2}}

Simplify

\frac{( 10 + 2 x ) ( 5 + x ) ^{2} - 2 ( 5 + x ) ( 10 x + x ^{2} )}{( ( 5 + x ) ^{2} ) ^{2}} : \frac{50}{( 5 + x ) ^{3}}

= \frac{50}{( 5 + x ) ^{3}}

\frac{d y}{d x} - \frac{2 x ^{3}}{y} = 0

\int \frac{10}{9 - 16 x ^{2}} d x

\int \frac{1}{x ^{2} + 4 x - 12} d x

y^{^{''}} + 6 y^{^{'}} + 8 y = 0, y (0) = 9

cos (e^{- 4 θ^{5}})

What is the derivative of f(x)=(10x+x^2)/((5+x)^2) ?
The derivative of f(x)=(10x+x^2)/((5+x)^2) is (50)/((5+x)^3)
What is the first derivative of f(x)=(10x+x^2)/((5+x)^2) ?
The first derivative of f(x)=(10x+x^2)/((5+x)^2) is (50)/((5+x)^3)