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Popular >

y^'=(y+5)(x+2)

Solution

y^{^{'}} = (y + 5) (x + 2)

Solution

y = e^{\frac{x ^{2}}{2} + 2 x + c_{1}} - 5

Solution steps

y^{'} (x) = (y + 5) (x + 2)

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + 2 x + c_{1}} - 5

y = e^{\frac{x ^{2}}{2} + 2 x + c_{1}} - 5

Popular Examples

integral from 0 to 1 of (18)/(4y-1)

\int_{0}^{1} \frac{18}{4 y - 1} d y

tangent of f(x)= 7/x ,\at x=4 tangent of

f (x) = \frac{7}{x}, at x = 4

f(x)=ln(cos^2(x))

f (x) = ln (cos^{2} (x))

limit as x approaches 0 of (e^x+x)^{4/x}

x \to 0 lim ((e^{x} + x)^{\frac{4}{x}})

integral of 1+x^2

\int 1 + x^{2} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=(y+5)(x+2) ?
The solution for y^'=(y+5)(x+2) is y=e^{(x^2)/2+2x+c_{1}}-5