What is the tangent of f(x)=x^2-7 ?

The tangent of f(x)=x^2-7 is y=2a_{0}x-a_{0}^2-7

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tangent of f(x)=x^2-7

tangent of

f (x) = x^{2} - 7

y = 2 a_{0} x - a_{0}^{2} - 7

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} - 7)

Find the slope of

f (x) = x^{2} - 7 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 7

x = a_{0} : m = 2 a_{0}

Find the line with slope m=

2 a_{0}

and passing through

(a_{0}, a_{0}^{2} - 7) : y = 2 a_{0} x - a_{0}^{2} - 7

y = 2 a_{0} x - a_{0}^{2} - 7

\int \frac{5}{( x + 1 ) ( x ^{2} + 4 )} d x

\int t^{2} 1 + t^{2} d t

\frac{d}{d x} (- x^{2} + 9)

\frac{7 e ^{x}}{( 7 + e ^{x} ) ^{2}}

\frac{d}{d t} (t^{r})

What is the tangent of f(x)=x^2-7 ?
The tangent of f(x)=x^2-7 is y=2a_{0}x-a_{0}^2-7