What is the solution for (dy)/(dx)= 1/x (y^2+0.6y),y(1)=0.9 ?

The solution for (dy)/(dx)= 1/x (y^2+0.6y),y(1)=0.9 is y=(0.36x^{0.6})/(1-0.6x^{0.6)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)= 1/x (y^2+0.6y),y(1)=0.9

\frac{d y}{d x} = \frac{1}{x} (y^{2} + 0.6 y), y (1) = 0.9

y = \frac{0.36 x ^{0.6}}{1 - 0.6 x ^{0.6}}

Solution steps

\frac{d y}{d x} = \frac{1}{x} (y^{2} + 0.6 y)

Solve separable ODE:

y = \frac{0.36 x ^{0.6}}{1 - 0.6 x ^{0.6}}

y = \frac{0.36 x ^{0.6}}{1 - 0.6 x ^{0.6}}

x \to 4 lim (∣ x ∣ - 3^{x})

\int_{0}^{2 π} x^{2} sin (n x) d x

\frac{7}{x - 2}

\int x i n^{2} x d x

\int \frac{x ^{2} - 81}{x ^{3}} d x

What is the solution for (dy)/(dx)= 1/x (y^2+0.6y),y(1)=0.9 ?
The solution for (dy)/(dx)= 1/x (y^2+0.6y),y(1)=0.9 is y=(0.36x^{0.6})/(1-0.6x^{0.6)}