What is (\partial)/(\partial x)(y^2sin(4x)) ?

The answer to (\partial)/(\partial x)(y^2sin(4x)) is y^2cos(4x)*4

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(\partial)/(\partial x)(y^2sin(4x))

\frac{\partial}{\partial x} (y^{2} sin (4 x))

y^{2} cos (4 x) \cdot 4

Solution steps

\frac{\partial}{\partial x} (y^{2} sin (4 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} \frac{\partial}{\partial x} (sin (4 x))

Apply the chain rule:

cos (4 x) \frac{\partial}{\partial x} (4 x)

= cos (4 x) \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (4 x) = 4

= y^{2} cos (4 x) \cdot 4

\frac{d}{d x} (2 ln (4 x))

\frac{d}{d x} (r x + s)

\int (2 x + 3)^{- 1} d x

\frac{d}{d s} (\frac{s - s}{s ^{2}})

3 - 2 x

What is (\partial)/(\partial x)(y^2sin(4x)) ?
The answer to (\partial)/(\partial x)(y^2sin(4x)) is y^2cos(4x)*4