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Popular >

2y^'-y=4

Solution

2 y^{^{'}} - y = 4

Solution

y = e^{\frac{t + c _{1}}{2}} - 4

Solution steps

2 y^{'} (t) - y = 4

Solve separable ODE:

y = e^{\frac{t + c _{1}}{2}} - 4

y = e^{\frac{t + c _{1}}{2}} - 4

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Frequently Asked Questions (FAQ)

What is the solution for 2y^'-y=4 ?
The solution for 2y^'-y=4 is y=e^{(t+c_{1})/2}-4