What is the derivative of sqrt(ln(-5x+2x^{-2)}) ?

The derivative of sqrt(ln(-5x+2x^{-2)}) is (-5x^3-4)/(2x(-5x^3+2)sqrt(ln(-5x^3+2)-2ln(x)))

What is the first derivative of sqrt(ln(-5x+2x^{-2)}) ?

The first derivative of sqrt(ln(-5x+2x^{-2)}) is (-5x^3-4)/(2x(-5x^3+2)sqrt(ln(-5x^3+2)-2ln(x)))

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\frac{d}{d x} (ln (- 5 x + 2 x^{- 2}))

\frac{- 5 x ^{3} - 4}{2 x ( - 5 x ^{3} + 2 ) ln ( - 5 x ^{3} + 2 ) - 2 ln ( x )}

Solution steps

\frac{d}{d x} (ln (- 5 x + 2 x^{- 2}))

Apply the chain rule:

\frac{1}{2 ln ( - 5 x + 2 x ^{- 2} )} \frac{d}{d x} (ln (- 5 x + 2 x^{- 2}))

= \frac{1}{2 ln ( - 5 x + 2 x ^{- 2} )} \frac{d}{d x} (ln (- 5 x + 2 x^{- 2}))

\frac{d}{d x} (ln (- 5 x + 2 x^{- 2})) = \frac{- 5 x ^{3} - 4}{x ( - 5 x ^{3} + 2 )}

= \frac{1}{2 ln ( - 5 x + 2 x ^{- 2} )} \cdot \frac{- 5 x ^{3} - 4}{x ( - 5 x ^{3} + 2 )}

Simplify

\frac{1}{2 ln ( - 5 x + 2 x ^{- 2} )} \cdot \frac{- 5 x ^{3} - 4}{x ( - 5 x ^{3} + 2 )} : \frac{- 5 x ^{3} - 4}{2 x ( - 5 x ^{3} + 2 ) ln ( - 5 x ^{3} + 2 ) - 2 ln ( x )}

= \frac{- 5 x ^{3} - 4}{2 x ( - 5 x ^{3} + 2 ) ln ( - 5 x ^{3} + 2 ) - 2 ln ( x )}

\frac{d}{d x} (x e^{x^{2} - y})

(1 + t) (2 t^{2} - 7)

\int \frac{4}{1 - x ^{2}} d x

y^{^{'}} = \frac{x y ^{2} + 2 x}{y ( 2 x ^{3} + x ^{2} + 3 )}

sin (3 ln (x))

What is the derivative of sqrt(ln(-5x+2x^{-2)}) ?
The derivative of sqrt(ln(-5x+2x^{-2)}) is (-5x^3-4)/(2x(-5x^3+2)sqrt(ln(-5x^3+2)-2ln(x)))
What is the first derivative of sqrt(ln(-5x+2x^{-2)}) ?
The first derivative of sqrt(ln(-5x+2x^{-2)}) is (-5x^3-4)/(2x(-5x^3+2)sqrt(ln(-5x^3+2)-2ln(x)))