What is the integral of 4/(sqrt(1-x^2)) ?

The integral of 4/(sqrt(1-x^2)) is 4arcsin(x)+C

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integral of 4/(sqrt(1-x^2))

\int \frac{4}{1 - x ^{2}} d x

4 arcsin (x) + C

Solution steps

\int \frac{4}{1 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{1 - x ^{2}} d x

Use the common integral:

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= 4 arcsin (x)

Add a constant to the solution

= 4 arcsin (x) + C

y^{^{'}} = \frac{x y ^{2} + 2 x}{y ( 2 x ^{3} + x ^{2} + 3 )}

sin (3 ln (x))

x \to 1 lim (2 x^{3} - 4 x^{2} + x + 3)

\frac{\partial}{\partial x} (3 ln (x + y) - 3 x)

n = 0 \sum \infty \frac{ln ( n )}{5 n}

What is the integral of 4/(sqrt(1-x^2)) ?
The integral of 4/(sqrt(1-x^2)) is 4arcsin(x)+C