What is area 2/x , 2/(x^2),1,6 ?

The answer to area 2/x , 2/(x^2),1,6 is 2ln(6)-5/3

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area 2/x , 2/(x^2),1,6

area

\frac{2}{x}, \frac{2}{x ^{2}}, 1, 6

2 ln (6) - \frac{5}{3}

Decimal Notation

1.91685 \dots

Solution steps

Apply the area formula:

\int_{1}^{6} \frac{2}{x} - \frac{2}{x ^{2}} d x

Solve

\int_{1}^{6} \frac{2}{x} - \frac{2}{x ^{2}} d x : 2 ln (6) - \frac{5}{3}

The area is:

= 2 ln (6) - \frac{5}{3}

\frac{d}{d x} (e^{- 15 x})

\int_{1}^{27} x^{\frac{1}{3}} d x

\int - \frac{1}{3} (\frac{x}{3})^{n} d x

f (x) = 2 x^{3} + 8 x^{2} + 3 x + 3

\frac{d}{d x} (x^{4} - 5 x^{2} + 9)

What is area 2/x , 2/(x^2),1,6 ?
The answer to area 2/x , 2/(x^2),1,6 is 2ln(6)-5/3