What is the integral of sin(1/6 x) ?

The integral of sin(1/6 x) is -6cos(1/6 x)+C

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integral of sin(1/6 x)

\int sin (\frac{1}{6} x) d x

- 6 cos (\frac{1}{6} x) + C

Solution steps

\int sin (\frac{1}{6} x) d x

Apply u-substitution

: \int sin (u) \cdot 6 d u

= \int sin (u) \cdot 6 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= 6 (- cos (u))

Substitute back

u = \frac{1}{6} x

= 6 (- cos (\frac{1}{6} x))

Simplify

= - 6 cos (\frac{1}{6} x)

Add a constant to the solution

= - 6 cos (\frac{1}{6} x) + C

\int_{1}^{2} \frac{1}{x ^{2} + 3 x} d x

\int [tan (x) + cot (x)] d x

\int_{0}^{\infty} 6 e^{- 6 x} d x

\int \frac{x ^{4}}{( 8 - x ^{5} ) ^{2}} d x

\frac{d}{d x} (cos (π))

What is the integral of sin(1/6 x) ?
The integral of sin(1/6 x) is -6cos(1/6 x)+C