What is the integral from 0 to infinity of 6e^{-6x} ?

The integral from 0 to infinity of 6e^{-6x} is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to infinity of 6e^{-6x}

\int_{0}^{\infty} 6 e^{- 6 x} d x

1

Solution steps

\int_{0}^{\infty} 6 e^{- 6 x} d x

Compute the indefinite integral:

\int 6 e^{- 6 x} d x = - e^{- 6 x} + C

Compute the boundaries:

\int_{0}^{\infty} 6 e^{- 6 x} d x = 0 - (- 1)

= 0 - (- 1)

Simplify

= 1

\int \frac{x ^{4}}{( 8 - x ^{5} ) ^{2}} d x

\frac{d}{d x} (cos (π))

n = 1 \sum \infty \frac{1}{( n + 1 ) ^{2}}

\int \frac{( 2 x - 1 ) ^{2}}{x - 1} d x

\int_{4}^{\infty} e^{- \frac{x}{3}} d x

What is the integral from 0 to infinity of 6e^{-6x} ?
The integral from 0 to infinity of 6e^{-6x} is 1