What is the solution for x^3(dy)/(dx)=y^2(x-4) ?

The solution for x^3(dy)/(dx)=y^2(x-4) is y=-(x^2)/(-x+2+c_{1)x^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^3(dy)/(dx)=y^2(x-4)

x^{3} \frac{d y}{d x} = y^{2} (x - 4)

y = - \frac{x ^{2}}{- x + 2 + c _{1} x ^{2}}

Solution steps

x^{3} \frac{d y}{d x} = y^{2} (x - 4)

Solve separable ODE:

y = - \frac{x ^{2}}{- x + 2 + c _{1} x ^{2}}

y = - \frac{x ^{2}}{- x + 2 + c _{1} x ^{2}}

\int \frac{1}{a ( sec ( x ) )} d x

\frac{d}{d x} (\frac{1 x + 1 + x}{x ^{2} - 1})

h

[x + (x + sin^{2} (x))^{4}]^{3}

\int_{2}^{7} (x^{2} - 2 x)^{2} d x

What is the solution for x^3(dy)/(dx)=y^2(x-4) ?
The solution for x^3(dy)/(dx)=y^2(x-4) is y=-(x^2)/(-x+2+c_{1)x^2}