What is the derivative of g(t)=(t-sqrt(t))/(t^{1/5)} ?

The derivative of g(t)=(t-sqrt(t))/(t^{1/5)} is (3(sqrt(t)-1))/(10t^{7/10)}+1/(2t^{1/5)}

What is the first derivative of g(t)=(t-sqrt(t))/(t^{1/5)} ?

The first derivative of g(t)=(t-sqrt(t))/(t^{1/5)} is (3(sqrt(t)-1))/(10t^{7/10)}+1/(2t^{1/5)}

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derivative of

g (t) = \frac{t - t}{t ^{\frac{1}{5}}}

\frac{3 ( t - 1 )}{10 t ^{\frac{7}{10}}} + \frac{1}{2 t ^{\frac{1}{5}}}

Solution steps

\frac{d}{d t} (\frac{t - t}{t ^{\frac{1}{5}}})

Simplify

\frac{t - t}{t ^{\frac{1}{5}}} : t^{\frac{3}{10}} (t - 1)

= \frac{d}{d t} (t^{\frac{3}{10}} (t - 1))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t^{\frac{3}{10}}, g = t - 1

= \frac{d}{d t} (t^{\frac{3}{10}}) (t - 1) + \frac{d}{d t} (t - 1) t^{\frac{3}{10}}

\frac{d}{d t} (t^{\frac{3}{10}}) = \frac{3}{10 t ^{\frac{7}{10}}}

\frac{d}{d t} (t - 1) = \frac{1}{2 t ^{\frac{1}{2}}}

= \frac{3}{10 t ^{\frac{7}{10}}} (t - 1) + \frac{1}{2 t ^{\frac{1}{2}}} t^{\frac{3}{10}}

Simplify

\frac{3}{10 t ^{\frac{7}{10}}} (t - 1) + \frac{1}{2 t ^{\frac{1}{2}}} t^{\frac{3}{10}} : \frac{3 ( t - 1 )}{10 t ^{\frac{7}{10}}} + \frac{1}{2 t ^{\frac{1}{5}}}

= \frac{3 ( t - 1 )}{10 t ^{\frac{7}{10}}} + \frac{1}{2 t ^{\frac{1}{5}}}

\frac{d y}{d x} = \frac{( 2 cos ( 2 x ) )}{3 + 2 y}

x \to \infty lim (\frac{1}{2 x})

\frac{d}{d x} (ln (ln (2 x^{3})))

\frac{\partial}{\partial y} ((x + y) e^{x})

\frac{x - 6}{x + 6}

What is the derivative of g(t)=(t-sqrt(t))/(t^{1/5)} ?
The derivative of g(t)=(t-sqrt(t))/(t^{1/5)} is (3(sqrt(t)-1))/(10t^{7/10)}+1/(2t^{1/5)}
What is the first derivative of g(t)=(t-sqrt(t))/(t^{1/5)} ?
The first derivative of g(t)=(t-sqrt(t))/(t^{1/5)} is (3(sqrt(t)-1))/(10t^{7/10)}+1/(2t^{1/5)}