What is (\partial)/(\partial y)(4/(y^2)+x) ?

The answer to (\partial)/(\partial y)(4/(y^2)+x) is -8/(y^3)

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(\partial)/(\partial y)(4/(y^2)+x)

\frac{\partial}{\partial y} (\frac{4}{y ^{2}} + x)

- \frac{8}{y ^{3}}

Solution steps

\frac{\partial}{\partial y} (\frac{4}{y ^{2}} + x)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (\frac{4}{y ^{2}}) + \frac{\partial}{\partial y} (x)

\frac{\partial}{\partial y} (\frac{4}{y ^{2}}) = - \frac{8}{y ^{3}}

\frac{\partial}{\partial y} (x) = 0

= - \frac{8}{y ^{3}} + 0

Simplify

= - \frac{8}{y ^{3}}

\int 9 x e^{- 4 x} d x

\frac{d}{d x} (lo g_{x} (x))

\int (3 x z^{2} + 2) d z

\frac{\partial}{\partial x} (- 3 y^{2})

\frac{d}{d x} (lo g_{10} (\frac{x ^{2} - 1}{x}))

What is (\partial)/(\partial y)(4/(y^2)+x) ?
The answer to (\partial)/(\partial y)(4/(y^2)+x) is -8/(y^3)