What is the derivative of sqrt(x^2+1)+x^2 ?

The derivative of sqrt(x^2+1)+x^2 is x/(sqrt(x^2+1))+2x

What is the first derivative of sqrt(x^2+1)+x^2 ?

The first derivative of sqrt(x^2+1)+x^2 is x/(sqrt(x^2+1))+2x

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derivative of

x^{2} + 1 + x^{2}

\frac{x}{x ^{2} + 1} + 2 x

Solution steps

\frac{d}{d x} (x^{2} + 1 + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2} + 1) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{2} + 1) = \frac{x}{x ^{2} + 1}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{x}{x ^{2} + 1} + 2 x

\int_{\frac{π}{4}}^{x} sec^{2} (t) d t

\int \frac{x + 1}{x ^{2} - 2 x - 1} d x

\int (2 t - 1)^{2} d t

\frac{d}{d x} (1 0^{t a n (π x)})

\frac{d}{d x} (3 \cdot cos (x))

What is the derivative of sqrt(x^2+1)+x^2 ?
The derivative of sqrt(x^2+1)+x^2 is x/(sqrt(x^2+1))+2x
What is the first derivative of sqrt(x^2+1)+x^2 ?
The first derivative of sqrt(x^2+1)+x^2 is x/(sqrt(x^2+1))+2x