What is the first (2sin(t))^' ?

The first (2sin(t))^' is 2cos(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2sin(t))^'

(2 sin (t))^{^{'}}

2 cos (t)

Solution steps

(2 sin (t))^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 (sin (t))^{^{'}}

Apply the common derivative:

(sin (t))^{'} = cos (t)

= 2 cos (t)

x \to 2 lim (x^{2} + 7 - x)

\frac{\partial}{\partial x} (y^{4} + 5 x y^{3})

\frac{d}{d x} (cos (5 x - 3))

\frac{- 2 x}{( x ^{2} - 1 ) ^{2}}

\int \frac{4 e ^{x}}{e ^{2 x} + 4 e ^{x} + 4} d x