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Popular >

integral of 1/(z^2)

Solution

\int \frac{1}{z ^{2}} d z

Solution

- \frac{1}{z} + C

Solution steps

\int \frac{1}{z ^{2}} d z

Apply the Power Rule

: - \frac{1}{z}

= - \frac{1}{z}

Add a constant to the solution

= - \frac{1}{z} + C

Popular Examples

derivative of f(x)=-5e^{-5x+2}derivative of

f (x) = - 5 e^{- 5 x + 2}

sum from n=2 to infinity of 1/(n^{1/2)}

n = 2 \sum \infty \frac{1}{n ^{\frac{1}{2}}}

(\partial)/(\partial x)(x^5y^3)

\frac{\partial}{\partial x} (x^{5} y^{3})

tangent of f(x)=3e^x+2x,(0,3)tangent of

f (x) = 3 e^{x} + 2 x, (0, 3)

y^'=((2x^4+y^4))/(xy^3)

y^{^{'}} = \frac{( 2 x ^{4} + y ^{4} )}{x y ^{3}}

Frequently Asked Questions (FAQ)

What is the integral of 1/(z^2) ?
The integral of 1/(z^2) is -1/z+C