What is the integral of (2x^{-3}) ?

The integral of (2x^{-3}) is -1/(x^2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (2x^{-3})

\int (2 x^{- 3}) d x

- \frac{1}{x ^{2}} + C

Solution steps

\int 2 x^{- 3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x^{- 3} d x

Apply the Power Rule

: - \frac{1}{2 x ^{2}}

= 2 (- \frac{1}{2 x ^{2}})

Simplify

2 (- \frac{1}{2 x ^{2}}) : - \frac{1}{x ^{2}}

= - \frac{1}{x ^{2}}

Add a constant to the solution

= - \frac{1}{x ^{2}} + C

\frac{d}{d x} (\frac{( x ^{2} - 1 ) ( x + 1 )}{x ^{2} - 2 x + 1})

\int \frac{e ^{x}}{( 1 + e ^{x} ) ^{2}} d x

4 x, 4 x - x^{2}, 0, 2

\frac{d}{d x} (\frac{x ^{3}}{6} + \frac{1}{2 x})

f (x) = - 21 x - 3