What is the derivative of (x^3/6+1/(2x)) ?

The derivative of (x^3/6+1/(2x)) is (x^2)/2-1/(2x^2)

What is the first derivative of (x^3/6+1/(2x)) ?

The first derivative of (x^3/6+1/(2x)) is (x^2)/2-1/(2x^2)

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\frac{d}{d x} (\frac{x ^{3}}{6} + \frac{1}{2 x})

\frac{x ^{2}}{2} - \frac{1}{2 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{6} + \frac{1}{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{6}) + \frac{d}{d x} (\frac{1}{2 x})

\frac{d}{d x} (\frac{x ^{3}}{6}) = \frac{x ^{2}}{2}

\frac{d}{d x} (\frac{1}{2 x}) = - \frac{1}{2 x ^{2}}

= \frac{x ^{2}}{2} - \frac{1}{2 x ^{2}}

f (x) = - 21 x - 3

y^{^{'}} = 3 + e^{- 5 t}

\frac{d y}{d x} = e^{x - y}, y (ln (3)) = ln (5)

\frac{\partial}{\partial y} (0.5 x^{2} + y^{2} - 3 x + 2 y - 5)

- 5

What is the derivative of (x^3/6+1/(2x)) ?
The derivative of (x^3/6+1/(2x)) is (x^2)/2-1/(2x^2)
What is the first derivative of (x^3/6+1/(2x)) ?
The first derivative of (x^3/6+1/(2x)) is (x^2)/2-1/(2x^2)