What is the first derivative of 6x+4/3 ?

The first derivative of 6x+4/3 is 6

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derivative of 6x+4/3

\frac{d}{d x} (6 x + \frac{4}{3})

6

Solution steps

\frac{d}{d x} (6 x + \frac{4}{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x) + \frac{d}{d x} (\frac{4}{3})

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (\frac{4}{3}) = 0

= 6 + 0

Simplify

= 6

y = x^{7}

n \to \infty lim (1 - \frac{1}{n})

cos (x) - sin (x), x = 0, y = 0

\frac{\partial}{\partial x} (\frac{y}{x} + \frac{x}{y})

\frac{d}{d x} (\frac{7 x ^{2} - 6 x + 4}{3 x + 2})