What is laplacetransform-4sin(3t) ?

The answer to laplacetransform-4sin(3t) is -(12)/(s^2+9)

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laplacetransform-4sin(3t)

laplace transform

- 4 sin (3 t)

- \frac{12}{s ^{2} + 9}

Solution steps

L {- 4 sin (3 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 4 L {sin (3 t)}

L {sin (3 t)} : \frac{3}{s ^{2} + 9}

= - 4 \cdot \frac{3}{s ^{2} + 9}

Refine

- 4 \frac{3}{s ^{2} + 9} : - \frac{12}{s ^{2} + 9}

= - \frac{12}{s ^{2} + 9}

\frac{d}{d x} ((4 x^{2} - 6 x) e^{x})

2 x^{2} y^{^{''}} + (y^{^{'}})^{3} = 2 x y^{^{'}}

\frac{d y}{d x} = - \frac{2 x ^{2} + y}{x ^{2} y - x}

\frac{d}{d y} (\frac{y ^{\frac{3}{2}}}{3} - y^{\frac{1}{2}})

\int \frac{x ^{2}}{x ^{3} + 3600} d x

What is laplacetransform-4sin(3t) ?
The answer to laplacetransform-4sin(3t) is -(12)/(s^2+9)