What is the integral of (x^2)/(sqrt(x^3+3600)) ?

The integral of (x^2)/(sqrt(x^3+3600)) is 2/3 sqrt(x^3+3600)+C

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integral of (x^2)/(sqrt(x^3+3600))

\int \frac{x ^{2}}{x ^{3} + 3600} d x

\frac{2}{3} x^{3} + 3600 + C

Solution steps

\int \frac{x ^{2}}{x ^{3} + 3600} d x

Apply u-substitution

: \int \frac{2}{3} d u

= \int \frac{2}{3} d u

Integral of a constant:

\int a d x = a x

= \frac{2}{3} u

Substitute back

u = x^{3} + 3600

= \frac{2}{3} x^{3} + 3600

Add a constant to the solution

= \frac{2}{3} x^{3} + 3600 + C

n = 1 \sum \infty cos (28)

y^{^{'}} = e^{x + 2 y}

7 y^{^{''}} + 14 y^{^{'}} - 21 y = 0

x \to 0 lim (\frac{x - 2}{x ^{2} - 4})

\frac{\partial}{\partial x} (x^{3} z - y x^{2} + z^{2})

What is the integral of (x^2)/(sqrt(x^3+3600)) ?
The integral of (x^2)/(sqrt(x^3+3600)) is 2/3 sqrt(x^3+3600)+C