What is inverse oflaplace 1/(6s) ?

The answer to inverse oflaplace 1/(6s) is 1/6 \H(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse oflaplace 1/(6s)

inverse laplace

\frac{1}{6 s}

\frac{1}{6} H (t)

Solution steps

L^{- 1} {\frac{1}{6 s}}

= L^{- 1} {\frac{1}{6} \cdot \frac{1}{s}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= \frac{1}{6} L^{- 1} {\frac{1}{s}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{a}{s}} = a H (t)

Where

H (t)

is Heaviside step function

= \frac{1}{6} H (t)

\int \frac{1}{θ ^{2}} cos (\frac{1}{θ}) d θ

\frac{\partial}{\partial x} (e^{s i n (2 x)})

\frac{d}{d x} (e^{t a n h (x)})

1 + x

\frac{d y}{d x} = - \frac{5 y}{50 + x}

What is inverse oflaplace 1/(6s) ?
The answer to inverse oflaplace 1/(6s) is 1/6 \H(t)