en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 24t^2+16t

Solution

\int 24 t^{2} + 16 t d t

Solution

8 t^{3} + 8 t^{2} + C

Solution steps

\int 24 t^{2} + 16 t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 24 t^{2} d t + \int 16 t d t

\int 24 t^{2} d t = 8 t^{3}

\int 16 t d t = 8 t^{2}

= 8 t^{3} + 8 t^{2}

Add a constant to the solution

= 8 t^{3} + 8 t^{2} + C

Popular Examples

tangent of f(x)=sqrt(x^2+24),\at x=5 tangent of

f (x) = x^{2} + 24, at x = 5

xy^'=5y-x,y(1)=1

x y^{^{'}} = 5 y - x, y (1) = 1

integral of (arccos(sqrt(x)))/(sqrt(x))

\int \frac{arccos ( x )}{x} d x

derivative of 2sin(x+sin^2(x))

\frac{d}{d x} (2 sin (x) + sin^{2} (x))

d/(dX)((X-3)^2+2)

\frac{d}{d X} ((X - 3)^{2} + 2)

Frequently Asked Questions (FAQ)

What is the integral of 24t^2+16t ?
The integral of 24t^2+16t is 8t^3+8t^2+C