What is the integral of (x^5)/(sqrt(u)) ?

The integral of (x^5)/(sqrt(u)) is (x^6)/(6sqrt(u))+C

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integral of (x^5)/(sqrt(u))

\int \frac{x ^{5}}{u} d x

\frac{x ^{6}}{6 u} + C

Solution steps

\int \frac{x ^{5}}{u} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{u} \cdot \int x^{5} d x

Apply the Power Rule

: \frac{x ^{6}}{6}

= \frac{1}{u} \cdot \frac{x ^{6}}{6}

Simplify

\frac{1}{u} \cdot \frac{x ^{6}}{6} : \frac{x ^{6}}{6 u}

= \frac{x ^{6}}{6 u}

Add a constant to the solution

= \frac{x ^{6}}{6 u} + C

x \to 0 lim (sin (0))

\frac{\partial}{\partial x} (200 (y - x^{2}))

x \to - 2 lim (\frac{x - 1}{x ^{2} - 4})

\int \frac{2 x}{x ^{3}} d x

\int_{- \frac{1}{2}}^{\frac{3}{2}} x - cos (π x) d x

What is the integral of (x^5)/(sqrt(u)) ?
The integral of (x^5)/(sqrt(u)) is (x^6)/(6sqrt(u))+C