What is the derivative of f(x)g(x) ?

The derivative of f(x)g(x) is x^2g

What is the first derivative of f(x)g(x) ?

The first derivative of f(x)g(x) is x^2g

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derivative of

f (x) g (x)

x^{2} g

Solution steps

\frac{d}{df} (f xgx)

Simplify

f xgx : f x^{2} g

= \frac{d}{df} (f x^{2} g)

Treat

x, g

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} g \frac{df}{df}

Apply the common derivative:

\frac{df}{df} = 1

= x^{2} g \cdot 1

Simplify

= x^{2} g

2 x^{2} + x - 1

x \to - 6 lim (\frac{( x ^{2} - 36 )}{x + 6})

\int \frac{2 e ^{x}}{e ^{2 x} + 1} d x

(4 x^{2} + 3 y^{2}) d x - 2 x y d y = 0

\int_{1}^{5} x^{3} ln (4 x) d x

What is the derivative of f(x)g(x) ?
The derivative of f(x)g(x) is x^2g
What is the first derivative of f(x)g(x) ?
The first derivative of f(x)g(x) is x^2g