What is the derivative of (sin(x)/(2-cos(x))) ?

The derivative of (sin(x)/(2-cos(x))) is (cos(x)(2-cos(x))-sin^2(x))/((2-cos(x))^2)

What is the first derivative of (sin(x)/(2-cos(x))) ?

The first derivative of (sin(x)/(2-cos(x))) is (cos(x)(2-cos(x))-sin^2(x))/((2-cos(x))^2)

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\frac{d}{d x} (\frac{sin ( x )}{2 - cos ( x )})

\frac{cos ( x ) ( 2 - cos ( x ) ) - sin ^{2} ( x )}{( 2 - cos ( x ) ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{sin ( x )}{2 - cos ( x )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( sin ( x ) ) ( 2 - cos ( x ) ) - \frac{d}{d x} ( 2 - cos ( x ) ) sin ( x )}{( 2 - cos ( x ) ) ^{2}}

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (2 - cos (x)) = sin (x)

= \frac{cos ( x ) ( 2 - cos ( x ) ) - sin ( x ) sin ( x )}{( 2 - cos ( x ) ) ^{2}}

sin (x) sin (x) = sin^{2} (x)

= \frac{cos ( x ) ( 2 - cos ( x ) ) - sin ^{2} ( x )}{( 2 - cos ( x ) ) ^{2}}

\int (\frac{x - 1}{x ^{2}}) d x

y^{^{''}} - 8 y^{^{'}} + 17 = 0

U (x) = - 0.04 x^{2} + 240 x - 10000

\int_{0}^{3} e^{x} - x^{2} d x

\frac{\partial}{\partial x} (y ln (x^{3} + y^{4} + 3) - 9)

What is the derivative of (sin(x)/(2-cos(x))) ?
The derivative of (sin(x)/(2-cos(x))) is (cos(x)(2-cos(x))-sin^2(x))/((2-cos(x))^2)
What is the first derivative of (sin(x)/(2-cos(x))) ?
The first derivative of (sin(x)/(2-cos(x))) is (cos(x)(2-cos(x))-sin^2(x))/((2-cos(x))^2)