What is the integral of (12)/(x^2+5x+6) ?

The integral of (12)/(x^2+5x+6) is 12(ln|x+2|-ln|x+3|)+C

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integral of (12)/(x^2+5x+6)

\int \frac{12}{x ^{2} + 5 x + 6} d x

12 (ln ∣ x + 2 ∣ - ln ∣ x + 3 ∣) + C

Solution steps

\int \frac{12}{x ^{2} + 5 x + 6} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 12 \cdot \int \frac{1}{x ^{2} + 5 x + 6} d x

Take the partial fraction of

\frac{1}{x ^{2} + 5 x + 6} : \frac{1}{x + 2} - \frac{1}{x + 3}

= 12 \cdot \int \frac{1}{x + 2} - \frac{1}{x + 3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 12 (\int \frac{1}{x + 2} d x - \int \frac{1}{x + 3} d x)

\int \frac{1}{x + 2} d x = ln ∣ x + 2 ∣

\int \frac{1}{x + 3} d x = ln ∣ x + 3 ∣

= 12 (ln ∣ x + 2 ∣ - ln ∣ x + 3 ∣)

Add a constant to the solution

= 12 (ln ∣ x + 2 ∣ - ln ∣ x + 3 ∣) + C

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What is the integral of (12)/(x^2+5x+6) ?
The integral of (12)/(x^2+5x+6) is 12(ln|x+2|-ln|x+3|)+C