What is the integral of 9x^2+4x-7 ?

The integral of 9x^2+4x-7 is 3x^3+2x^2-7x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 9x^2+4x-7

\int 9 x^{2} + 4 x - 7 d x

3 x^{3} + 2 x^{2} - 7 x + C

Solution steps

\int 9 x^{2} + 4 x - 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 x^{2} d x + \int 4 x d x - \int 7 d x

\int 9 x^{2} d x = 3 x^{3}

\int 4 x d x = 2 x^{2}

\int 7 d x = 7 x

= 3 x^{3} + 2 x^{2} - 7 x

Add a constant to the solution

= 3 x^{3} + 2 x^{2} - 7 x + C

\frac{\partial}{\partial z} (ln (x^{2} + y^{2} + z^{2}))

\frac{\partial}{\partial x} (x^{8} y^{5} - x^{7} y^{4})

4^{x^{3}}

\frac{d}{d x} (x coth (6 + x^{2}))

\int \frac{e ^{x}}{( x - 1 )} d x