What is the d/(dt)(sin^4(t)) ?

The d/(dt)(sin^4(t)) is 4sin^3(t)cos(t)

What is the first d/(dt)(sin^4(t)) ?

The first d/(dt)(sin^4(t)) is 4sin^3(t)cos(t)

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\frac{d}{d t} (sin^{4} (t))

4 sin^{3} (t) cos (t)

Solution steps

\frac{d}{d t} (sin^{4} (t))

Apply the chain rule:

4 (sin (t))^{3} \frac{d}{d t} (sin (t))

= 4 (sin (t))^{3} \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= 4 (sin (t))^{3} cos (t)

Simplify

= 4 sin^{3} (t) cos (t)

(t^{2} - 20 t + 75) \frac{d y}{d t} = y

f (x) = 6 x^{2} e^{6 x} + 2 x e^{6 x}

\frac{\partial}{\partial x} (ln (x^{7} + y^{7}))

\int_{- 1}^{3} \frac{x ^{3}}{4} + x^{2} - \frac{5}{4} d x

\int ln (1 + x) d x

What is the d/(dt)(sin^4(t)) ?
The d/(dt)(sin^4(t)) is 4sin^3(t)cos(t)
What is the first d/(dt)(sin^4(t)) ?
The first d/(dt)(sin^4(t)) is 4sin^3(t)cos(t)