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Popular >

2y^'+5y=4

Solution

2 y^{^{'}} + 5 y = 4

Solution

y = - \frac{e ^{\frac{- 5 t - c _{1}}{2}}}{5} + \frac{4}{5}

Solution steps

2 y^{'} (t) + 5 y = 4

Solve separable ODE:

y = - \frac{e ^{\frac{- 5 t - c _{1}}{2}}}{5} + \frac{4}{5}

y = - \frac{e ^{\frac{- 5 t - c _{1}}{2}}}{5} + \frac{4}{5}

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Frequently Asked Questions (FAQ)

What is the solution for 2y^'+5y=4 ?
The solution for 2y^'+5y=4 is y=-(e^{(-5t-c_{1})/2})/(5)+4/5