What is the derivative of 10arccot(x) ?

The derivative of 10arccot(x) is -(10)/(x^2+1)

What is the first derivative of 10arccot(x) ?

The first derivative of 10arccot(x) is -(10)/(x^2+1)

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\frac{d}{d x} (10 arccot (x))

- \frac{10}{x ^{2} + 1}

Solution steps

\frac{d}{d x} (10 arccot (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{d}{d x} (arccot (x))

Apply the common derivative:

\frac{d}{d x} (arccot (x)) = - \frac{1}{x ^{2} + 1}

= 10 (- \frac{1}{x ^{2} + 1})

Simplify

10 (- \frac{1}{x ^{2} + 1}) : - \frac{10}{x ^{2} + 1}

= - \frac{10}{x ^{2} + 1}

\int \frac{- x}{4 - x ^{2}} d x

\frac{d}{d x} (x y^{2} + x^{2} y^{3} + x^{3} y^{4})

x^{2} + y^{2} = 25, (- 3, 4)

\frac{d}{d x} (x^{3} (1 - x)^{2})

\int x sec^{2} (x) d x

What is the derivative of 10arccot(x) ?
The derivative of 10arccot(x) is -(10)/(x^2+1)
What is the first derivative of 10arccot(x) ?
The first derivative of 10arccot(x) is -(10)/(x^2+1)