What is the derivative of g(x)=sqrt(4-x) ?

The derivative of g(x)=sqrt(4-x) is -1/(2sqrt(4-x))

What is the first derivative of g(x)=sqrt(4-x) ?

The first derivative of g(x)=sqrt(4-x) is -1/(2sqrt(4-x))

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derivative of

g (x) = 4 - x

- \frac{1}{2 4 - x}

Solution steps

\frac{d}{d x} (4 - x)

Apply the chain rule:

\frac{1}{2 4 - x} \frac{d}{d x} (4 - x)

= \frac{1}{2 4 - x} \frac{d}{d x} (4 - x)

\frac{d}{d x} (4 - x) = - 1

= \frac{1}{2 4 - x} (- 1)

Simplify

= - \frac{1}{2 4 - x}

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\int 16 sin^{2} (x) cos^{2} (x) d x

\int_{0}^{5} (7 x - x^{2}) - (2 x) d x

x \to \infty lim (5 + \frac{6}{x})

What is the derivative of g(x)=sqrt(4-x) ?
The derivative of g(x)=sqrt(4-x) is -1/(2sqrt(4-x))
What is the first derivative of g(x)=sqrt(4-x) ?
The first derivative of g(x)=sqrt(4-x) is -1/(2sqrt(4-x))