What is the integral of (2x^4+8x^3-x)/(x^3) ?

The integral of (2x^4+8x^3-x)/(x^3) is x^2+8x+1/x+C

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integral of (2x^4+8x^3-x)/(x^3)

\int \frac{2 x ^{4} + 8 x ^{3} - x}{x ^{3}} d x

x^{2} + 8 x + \frac{1}{x} + C

Solution steps

\int \frac{2 x ^{4} + 8 x ^{3} - x}{x ^{3}} d x

Expand

\frac{2 x ^{4} + 8 x ^{3} - x}{x ^{3}} : 2 x + 8 - \frac{1}{x ^{2}}

= \int 2 x + 8 - \frac{1}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x d x + \int 8 d x - \int \frac{1}{x ^{2}} d x

\int 2 x d x = x^{2}

\int 8 d x = 8 x

\int \frac{1}{x ^{2}} d x = - \frac{1}{x}

= x^{2} + 8 x - (- \frac{1}{x})

Simplify

= x^{2} + 8 x + \frac{1}{x}

Add a constant to the solution

= x^{2} + 8 x + \frac{1}{x} + C

n = 2 \sum \infty ln (\frac{n}{n + 1})

f (x) = e^{x} + x^{e}

\frac{d}{d x} ((x + 1) (x - 2))

y (x + 9) + y^{^{'}} = 0, y (- 18) = 1

\frac{\partial}{\partial x} (x^{2} + y^{2} + z)

What is the integral of (2x^4+8x^3-x)/(x^3) ?
The integral of (2x^4+8x^3-x)/(x^3) is x^2+8x+1/x+C