What is the derivative of (x+1(x-2)) ?

The derivative of (x+1(x-2)) is 2x-1

What is the first derivative of (x+1(x-2)) ?

The first derivative of (x+1(x-2)) is 2x-1

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\frac{d}{d x} ((x + 1) (x - 2))

2 x - 1

Solution steps

\frac{d}{d x} ((x + 1) (x - 2))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x + 1, g = x - 2

= \frac{d}{d x} (x + 1) (x - 2) + \frac{d}{d x} (x - 2) (x + 1)

\frac{d}{d x} (x + 1) = 1

\frac{d}{d x} (x - 2) = 1

= 1 \cdot (x - 2) + 1 \cdot (x + 1)

Simplify

1 \cdot (x - 2) + 1 \cdot (x + 1) : 2 x - 1

= 2 x - 1

y (x + 9) + y^{^{'}} = 0, y (- 18) = 1

\frac{\partial}{\partial x} (x^{2} + y^{2} + z)

y = x (x^{4} - x^{3})

y = \frac{36 x}{x ^{2} + 36}, (- 3, - \frac{12}{5})

\frac{d}{d x} (21 x + x^{2})

What is the derivative of (x+1(x-2)) ?
The derivative of (x+1(x-2)) is 2x-1
What is the first derivative of (x+1(x-2)) ?
The first derivative of (x+1(x-2)) is 2x-1