What is the tangent of y=(36x)/(x^2+36),(-3,-12/5) ?

The tangent of y=(36x)/(x^2+36),(-3,-12/5) is y= 12/25 x-24/25

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tangent of y=(36x)/(x^2+36),(-3,-12/5)

tangent of

y = \frac{36 x}{x ^{2} + 36}, (- 3, - \frac{12}{5})

y = \frac{12}{25} x - \frac{24}{25}

Solution steps

Find the slope of

y = \frac{36 x}{x ^{2} + 36} : \frac{d y}{d x} = \frac{36 ( - x ^{2} + 36 )}{( x ^{2} + 36 ) ^{2}}

Compute the slope of

y = \frac{36 x}{x ^{2} + 36}

(- 3, - \frac{12}{5}) : m = \frac{12}{25}

Find the line with slope m=

\frac{12}{25}

and passing through

(- 3, - \frac{12}{5}) : y = \frac{12}{25} x - \frac{24}{25}

y = \frac{12}{25} x - \frac{24}{25}

\frac{d}{d x} (21 x + x^{2})

\frac{d}{d x} (e^{2 x})

\frac{\partial}{\partial x} (6 x + y^{3})

\frac{d}{d x} (x^{3} - 6 x^{2} + 12 x)

\frac{d}{d x} (x^{2} - 2 x + 5)

What is the tangent of y=(36x)/(x^2+36),(-3,-12/5) ?
The tangent of y=(36x)/(x^2+36),(-3,-12/5) is y= 12/25 x-24/25