What is the sum from n=0 to infinity of (n+1)/(2^n) ?

The sum from n=0 to infinity of (n+1)/(2^n) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of (n+1)/(2^n)

n = 0 \sum \infty \frac{n + 1}{2 ^{n}}

converges

Solution steps

n = 0 \sum \infty \frac{n + 1}{2 ^{n}}

Apply Series Ratio Test:

converges

= converges

x \to 0 lim (\frac{( 2 x - 1 )}{x})

f (x) = \frac{5}{x ^{5}} + \frac{3}{x ^{2}}

\int 4 sin^{6} (x) cos (x) d x

h \to \frac{1}{2} lim (\frac{8 h ^{3} - 1}{1 - 2 h})

\frac{8}{tan ^{3} ( \frac{x}{2} )}

What is the sum from n=0 to infinity of (n+1)/(2^n) ?
The sum from n=0 to infinity of (n+1)/(2^n) is converges