What is the derivative of f(x)=4x^3-18x^2 ?

The derivative of f(x)=4x^3-18x^2 is 12x^2-36x

What is the first derivative of f(x)=4x^3-18x^2 ?

The first derivative of f(x)=4x^3-18x^2 is 12x^2-36x

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derivative of

f (x) = 4 x^{3} - 18 x^{2}

12 x^{2} - 36 x

Solution steps

\frac{d}{d x} (4 x^{3} - 18 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (18 x^{2})

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (18 x^{2}) = 36 x

= 12 x^{2} - 36 x

y^{^{'}} = 4 y (3 - y)

\int y e^{- y x} d x

n = 0 \sum \infty (- \frac{3}{2})^{- 2 n}

f (x) = \frac{6}{3 x + 1}, (- 1, - 3)

x \to 2 lim (\frac{( ∣ x - 2 ∣ )}{x})

What is the derivative of f(x)=4x^3-18x^2 ?
The derivative of f(x)=4x^3-18x^2 is 12x^2-36x
What is the first derivative of f(x)=4x^3-18x^2 ?
The first derivative of f(x)=4x^3-18x^2 is 12x^2-36x