What is the solution for y^{''}+y=e^{-x} ?

The solution for y^{''}+y=e^{-x} is y=c_{1}cos(x)+c_{2}sin(x)+1/2 e^{-x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+y=e^{-x}

y^{^{''}} + y = e^{- x}

y = c_{1} cos (x) + c_{2} sin (x) + \frac{1}{2} e^{- x}

Solution steps

y^{''} (x) + y = e^{- x}

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + \frac{1}{2} e^{- x}

y = c_{1} cos (x) + c_{2} sin (x) + \frac{1}{2} e^{- x}

y = x (49.7)

\int \frac{1}{e ^{- 2 x}} d x

\int 2 x^{2} sin (π x) d x

\int \frac{y ^{4} + 2 y ^{2}}{y} d y

f (x) = arccsc (3 x)

What is the solution for y^{''}+y=e^{-x} ?
The solution for y^{''}+y=e^{-x} is y=c_{1}cos(x)+c_{2}sin(x)+1/2 e^{-x}