What is the derivative of 8x-2x^3 ?

The derivative of 8x-2x^3 is 8-6x^2

What is the first derivative of 8x-2x^3 ?

The first derivative of 8x-2x^3 is 8-6x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (8 x - 2 x^{3})

8 - 6 x^{2}

Solution steps

\frac{d}{d x} (8 x - 2 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) - \frac{d}{d x} (2 x^{3})

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

= 8 - 6 x^{2}

\int x^{3} x^{4} + 2 d x

(3 - 5 x e^{x}) (3 x + 2)

\frac{\partial}{\partial x} (e^{- \frac{x ^{2}}{4 d ^{2}}})

(1 + cos (t)) (\frac{d y}{d t}) = (1 + e^{- y}) sin (t)

f (x) = (x^{2} + 36) (2 x + 21)

What is the derivative of 8x-2x^3 ?
The derivative of 8x-2x^3 is 8-6x^2
What is the first derivative of 8x-2x^3 ?
The first derivative of 8x-2x^3 is 8-6x^2