What is (\partial)/(\partial x)(x^2-xy) ?

The answer to (\partial)/(\partial x)(x^2-xy) is 2x-y

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(\partial)/(\partial x)(x^2-xy)

\frac{\partial}{\partial x} (x^{2} - x y)

2 x - y

Solution steps

\frac{\partial}{\partial x} (x^{2} - x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (x y) = y

= 2 x - y

\int \frac{1}{( 4 x ^{2} - 24 x + 7 ) ^{\frac{3}{2}}} d x

\int 2 sin (x) - sec^{2} (x) d x

\frac{\partial}{\partial x} (6 x y - 12)

\int 2 tan (x) sec^{3} (x) d x

\frac{d}{d x} (\frac{π}{( 2 x ) ^{5}})

What is (\partial)/(\partial x)(x^2-xy) ?
The answer to (\partial)/(\partial x)(x^2-xy) is 2x-y