What is the integral of 2sin(x)-sec^2(x) ?

The integral of 2sin(x)-sec^2(x) is -2cos(x)-tan(x)+C

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integral of 2sin(x)-sec^2(x)

\int 2 sin (x) - sec^{2} (x) d x

- 2 cos (x) - tan (x) + C

Solution steps

\int 2 sin (x) - sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 sin (x) d x - \int sec^{2} (x) d x

\int 2 sin (x) d x = - 2 cos (x)

\int sec^{2} (x) d x = tan (x)

= - 2 cos (x) - tan (x)

Add a constant to the solution

= - 2 cos (x) - tan (x) + C

\frac{\partial}{\partial x} (6 x y - 12)

\int 2 tan (x) sec^{3} (x) d x

\frac{d}{d x} (\frac{π}{( 2 x ) ^{5}})

y = \frac{x ^{2} - 4 x + 3}{x ^{2}}

\int_{1}^{2} \frac{1}{2 x - 1} d x

What is the integral of 2sin(x)-sec^2(x) ?
The integral of 2sin(x)-sec^2(x) is -2cos(x)-tan(x)+C