What is derivative of f(x)=(b/(a+z^2))^7 ?

The answer to derivative of f(x)=(b/(a+z^2))^7 is (dz)/(dx)=0

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derivative of f(x)=(b/(a+z^2))^7

derivative of

f (x) = (\frac{b}{a + z ^{2}})^{7}

\frac{d z}{d x} = 0

Solution steps

f (x) = (\frac{b}{a + z ^{2}})^{7}

Treat

z

z (x)

Differentiate both sides:

0 = - \frac{14 b ^{7} z \frac{d z}{d x}}{( a + z ^{2} ) ^{8}}

Isolate

\frac{d z}{d x} : \frac{d z}{d x} = 0

\frac{d z}{d x} = 0

\int \frac{( 2 x + 3 )}{x + 2} d x

n = 1 \sum \infty \frac{5 n}{2 n + 5}

\frac{d}{d x} (\frac{25 - x ^{2}}{4 x})

\frac{\partial}{\partial x} (- 12 x y)

x y^{^{'}} - 3 y = 0

What is derivative of f(x)=(b/(a+z^2))^7 ?
The answer to derivative of f(x)=(b/(a+z^2))^7 is (dz)/(dx)=0